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Single-phase, DC and three-phase, with the algebra worked out

Voltage Drop Formula Explained

This page walks through the voltage drop formula itself, where each term comes from, why single-phase and three-phase circuits use different multipliers, and how to rearrange the formula to solve for wire size or maximum distance instead of voltage drop. If you just want a number, the voltage drop calculator does this arithmetic for you, this page is for understanding what it is doing.

The formula

For a single-phase or DC circuit:

VD = (2 × K × I × L) ÷ CM

For a three-phase circuit:

VD = (1.732 × K × I × L) ÷ CM

VD is the voltage drop in volts, K is a constant for the conductor material, I is the load current in amps, L is the one-way length of the run in feet, and CM is the conductor's cross-sectional area in circular mils. Every term is explained below.

Where the '2' and the '1.732' come from

In a single-phase or DC circuit, current has to travel out to the load through one conductor and back through another (the neutral, or the second hot leg on a 240V circuit). Both conductors have resistance, so the voltage drop happens twice, once on the way out and once on the way back, that is why the formula multiplies by 2 rather than treating it as a single one-way run.

In a balanced three-phase circuit, the relationship between the three phase conductors is different, the vector (phasor) math for a balanced three-phase load works out to a factor of the square root of 3, approximately 1.732, instead of 2. This is a standard result from three-phase circuit theory, not specific to voltage drop, the same square-root-of-3 factor shows up in three-phase power calculations generally.

The K constant (resistivity)

K represents how much a specific conductor material resists the flow of current, in units of ohm-circular-mils per foot. It comes from the same NEC Chapter 9, Table 8 data as the circular-mil values. The two values used almost universally in practice:

Circular mils (CM) and wire size

Circular mils measure a conductor's cross-sectional area, a larger circular-mil number means a physically thicker conductor with less resistance per foot. Wire sizes below 4/0 AWG use the American Wire Gauge system (a smaller AWG number is a thicker wire), sizes above 4/0 are specified directly in thousands of circular mils, written as kcmil (for example, 250 kcmil is 250,000 circular mils). See the full AWG-to-circular-mils reference table for every standard size from 14 AWG to 1000 kcmil.

Solving for wire size or maximum distance instead of voltage drop

The same formula rearranges algebraically to answer two other common questions:

  1. To find the minimum circular mils (and therefore the minimum wire size) for a target voltage drop: CM = (2 x K x I x L) / VD (or 1.732 in place of 2 for three-phase). Plug in your target VD (for example, 3% of your supply voltage) and solve for CM, then pick the smallest standard wire size with a circular-mil value at or above that result.
  2. To find the maximum one-way distance for a target voltage drop: L = (VD x CM) / (2 x K x I) (or 1.732 for three-phase). This is exactly how the maximum-distance columns on the voltage drop chart page were generated.
  3. In both cases it is usually faster to try a few wire sizes or distances in the calculator directly and read off the percentage, rather than solving the algebra by hand, the calculator uses the identical formula and the exact NEC Chapter 9, Table 8 circular-mil values.

A worked example, start to finish

Suppose a 120V single-phase branch circuit carries a 20A load over a 100 ft one-way run of 12 AWG copper wire. From the reference table, 12 AWG copper has a circular-mil area of 6,530. Applying the formula:

VD = (2 × 12.9 × 20 × 100) ÷ 6,530 = 51,600 ÷ 6,530 ≈ 7.90V

As a percentage of the 120V supply: 7.90 ÷ 120 × 100 ≈ 6.58%, which is above the NEC-recommended 3% branch-circuit guideline. Moving up to 10 AWG copper (10,380 circular mils) instead: VD = (2 × 12.9 × 20 × 100) ÷ 10,380 ≈ 4.97V, or about 4.14%, still above 3% but now inside the 5% combined guideline. Moving up again to 8 AWG (16,510 circular mils) brings the drop down to about 3.13V, or roughly 2.60%, comfortably under the 3% target. This step-by-step trial is exactly what the voltage drop calculator lets you do instantly by changing the wire size dropdown and reading the new percentage, entirely in your browser, see the privacy policy for details.

Frequently asked questions

What is the voltage drop formula for single phase?
VD = (2 x K x I x L) / CM, where K is 12.9 for copper or 21.2 for aluminum, I is the load current in amps, L is the one-way length in feet, and CM is the conductor's circular-mil area. DC circuits use the identical formula.
What is the voltage drop formula for three phase?
VD = (1.732 x K x I x L) / CM, the same formula as single-phase except the multiplier is 1.732 (the square root of 3) instead of 2, reflecting the phase relationship in a balanced three-phase circuit.
Why is the three-phase voltage drop lower than single-phase for the same current and distance?
Because 1.732 is smaller than 2. For identical current, wire size, length and material, the three-phase formula produces a lower voltage drop in volts than the single-phase formula.
How do I solve the formula for wire size instead of voltage drop?
Rearrange to CM = (2 x K x I x L) / VD (or use 1.732 for three-phase), plug in your target voltage drop in volts, then pick the smallest standard wire size whose circular-mil value from the reference table is at or above the result.
Is K always exactly 12.9 for copper?
12.9 is the standard, widely used approximate value for copper at about 75 degrees Celsius, taken from NEC Chapter 9, Table 8. The exact resistivity of copper varies slightly with temperature and conductor stranding, but 12.9 (and 21.2 for aluminum) is the figure used throughout the electrical trade for this calculation.

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